It's based on the the number of "active" or "dramatically important" opponents. Followers are not "important" enough to cause MO penalties (that's why they are followers, not Heroes/Villains).
> > I think what you're asking is three attacks, and so three defensve die
> > rolls:
> > Player 1 defends aganist Lunar 1 with no penalty.
> > Player 1 defends against Lunar 2 with a -3 penalty
> > Player 1 defends against Lunar 3 with a -6 penalty
> >
>
> Exactly. So that's the "straight up numbers" way to do it. The other is
where Lunar 1 has
> been augmented by Lunars 2 and 3. As mentioned above, Lunar 1 gets bonuses
from
> the augmentation, and Player 1 rolls as normal. It is effectively a one on
one battle, with
> Lunars 2 and 3 tied to Lunar 1.
Yep, the extra lunars (2 & 3) are treated as followers of Lunar 1 (including getting one level worse damage if defeated).
> What is interesting to note is that if there were 3 players against the
three Lunars, you
> could still have Lunars 2 and 3 augmenting Lunar 1. And in this case, even
though
> Lunar 1 would be defending 3 times, he would get no MO penalties, because
Lunars 2
> and 3 would cancel the numerical advantage of the Players.
>
> (At least as I understand it all)
Correct. Each follower "blocks" one opponent from inflicting an MO penalty on both defence *and* attack. Lunar 1 (with 2&3 as followers) would be able to *attack* all three player heroes without the -6 MO penalty he would have without followers.
RR
It is by my order and for the good of the state that the bearer of this has
done what he has done.
- Richelieu
Powered by hypermail