> So in this case if Boomer's opponent was using his fist (i.e. ^0)
> and bids 9AP then, yes, 9-(9-0) = no effect,
IIRC, bids cannot be reduced to less than 1 AP, so a 3x transfer in this case would be max(9-9, 1) x 3 = 3. Which would indicate to me that Boomer's opponent's best bet is probably to always bid 1, because he'd have to bid 11 to get any greater effect. Unless, of course, he has so many AP (a couple dozen followers, perhaps) that the difference between 1 and 11 is negligible. Or is it the intention of the rules that his opponent cannot bid less than 10? If so, what happens when said opponent is a lowly narrator character not allowed to bid more than current AP and has only 9 remaining? Is he forbidden to act directly? (I.e., can he only take unrelated actions or attempt to find an ability that Boomer cannot resist with the ability to which the edge/handicap is applied?)
> If either lose when it is their bid (i.e. non-bidder wins), edges
> do not come int play when calculating losses/transfer.
There are those of us who think that edges ought to work the same no matter who is the bidder (i.e., read the rule as saying an edge applies to the loser of an exchange, no matter who initiated it); it is my impression from reading the archives that going against the statement above is a reasonably popular house rule.
Also, be careful with this even under the official interpretation: Boomer's armor ^9 and his opponent's bare fist ^0 mean his opponent has a ^-9 handicap (negative edge), applied to decrease the number of AP Boomer loses (on the opponent's bid only, in Roderick's clarification), but Boomer's sorcery-enhanced enchanted iron battleaxe ^7 vs. the opponent's leather armor ^1 means Boomer has a ^6 edge applied to increase the number of AP his opponent loses (only on Boomer's bid, in Roderick's clarification). This distinction is presumably why some people feel weapon and armor ranks are too complicated to be worth using.
So when you increase your armor's rank, you really are giving your opponent a net handicap, without needing to overcome the resistance of enchanting *him*.
Ryan Caveney
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